Kareem Jackson named AFC Defensive Player of the Week

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ENGLEWOOD, Colo. Denver Broncos safety Kareem Jackson was named AFC Defensive Player of the Week for his performance in Denver’s 38-24 win against the Houston Texans, the NFL announced on Wednesday.

This marks the first conference recognition of Jackson’s career. He also is the first Bronco to be named AFC Defensive Player of the Week since outside linebacker Von Miller in 2018 (Week 11).

Returning to Houston, where he spent his first nine NFL seasons, Jackson in Week 14 totaled 11 tackles, one interception (4 yds.), three passes defensed and a fumble returned 70 yards for a touchdown. He became just the third player in NFL history with at least 10 tackles, a fumble returned for a touchdown and an interception in a single game (first since Brian Urlacher vs. Atl., 9/11/11).

Playing in his 152nd career game, his 11 tackles against Houston equaled his career high and tied for fifth among all AFC players in Week 14 (tied for most among AFC defensive backs).

Overall, Jackson’s honor represents the 34th time a Broncos player has been named AFC Defensive Player of the Week since the award was initiated by the NFL in 1984.